
Вопрос задан 29.10.2023 в 20:22.
Предмет Математика.
Спрашивает Рутковская Алиса.
Четыре билета на концерт распределили между 16 мальчиками и 12 девочками. Найти вероятность того,
что 2 билета достанутся мальчикам и 2 девочкам

Ответы на вопрос

Отвечает Лунёв Миша.
Ответ:
16+12=28
28:4=7
ответ:7
Пошаговое объяснение:



Отвечает нейросеть ChatGpt. Будьте внимательны, ответы нейросети могут содержать ошибочные или выдуманные данные.
#### Problem Statement
Four concert tickets are distributed among 16 boys and 12 girls. We need to find the probability that 2 tickets will go to boys and 2 tickets will go to girls.
#### Solution
To find the probability, we need to calculate the number of favorable outcomes and the total number of possible outcomes.
##### Total Number of Possible Outcomes
The total number of ways to distribute the 4 tickets among the 28 children can be calculated using combinations. We can choose 2 children out of 28 to receive the tickets, which can be represented as C(28, 2). The formula for combinations is:
C(n, r) = n! / (r! * (n-r)!)
where n is the total number of items and r is the number of items to be chosen.
Using this formula, we can calculate the total number of possible outcomes:
C(28, 2) = 28! / (2! * (28-2)!) = 28! / (2! * 26!) = (28 * 27) / (2 * 1) = 378
Therefore, there are 378 possible outcomes.
##### Number of Favorable Outcomes
To calculate the number of favorable outcomes, we need to consider that 2 tickets should go to boys and 2 tickets should go to girls.
The number of ways to choose 2 boys out of 16 can be calculated using combinations: C(16, 2) = 16! / (2! * (16-2)!) = (16 * 15) / (2 * 1) = 120.
Similarly, the number of ways to choose 2 girls out of 12 can be calculated using combinations: C(12, 2) = 12! / (2! * (12-2)!) = (12 * 11) / (2 * 1) = 66.
To find the number of favorable outcomes, we need to multiply the number of ways to choose 2 boys and 2 girls: 120 * 66 = 7,920.
Therefore, there are 7,920 favorable outcomes.
##### Probability
The probability can be calculated by dividing the number of favorable outcomes by the total number of possible outcomes:
Probability = Number of Favorable Outcomes / Total Number of Possible Outcomes
Probability = 7,920 / 378 = 20/63 ≈ 0.317
Therefore, the probability that 2 tickets will go to boys and 2 tickets will go to girls is approximately 0.317.
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