Question

Пожалуйста, срочно.. два стрелка делают по два выстрела каждый. вероятность попадания в цель для первого и второго стрелка равна соответственно 0.60 и 0.70. х-число попаданий. какова вероятность того, что промахов было хотя бы 2.

Answer 1

Они не просохнуть они стрелки

Answer 2

#### Probability of Missing at Least 2 Shots To calculate the probability of missing at least 2 shots, we need to consider the complementary event, which is the probability of hitting 0 or 1 shot. Let's denote the probability of hitting a shot for the first shooter as **p1 = 0.60** and for the second shooter as **p2 = 0.70**. The probability of hitting 0 shots for both shooters is given by **(1 - p1) * (1 - p2)**. The probability of hitting 1 shot for the first shooter and missing the shot for the second shooter is given by **p1 * (1 - p2)**. Similarly, the probability of missing the shot for the first shooter and hitting 1 shot for the second shooter is given by **(1 - p1) * p2**. Therefore, the probability of missing at least 2 shots is: **P(missing at least 2 shots) = (1 - p1) * (1 - p2) + p1 * (1 - p2) + (1 - p1) * p2** Now, let's substitute the values of **p1 = 0.60** and **p2 = 0.70** into the equation and calculate the probability. **P(missing at least 2 shots) = (1 - 0.60) * (1 - 0.70) + 0.60 * (1 - 0.70) + (1 - 0.60) * 0.70** Calculating the above expression will give us the probability of missing at least 2 shots.