Question

48+х,при х= 0,6,17 12у,при у=3,6,40

Answer 1

48+0,6=48,6
48+17=65
12*3,6=43,2
12*40=480

Answer 2

48+0=48

48+6=54

48+17=65

12*3=36

12*6=72

12*40=480

Answer 3

It seems like you have two expressions, one involving the variable $x$ and the other involving the variable $y$. Let's substitute the given values for $x$ and $y$ into their respective expressions.

1. For the expression $48 + x$ when $x = 0, 6, 17$:

   • For $x = 0$: $48 + 0 = 48$
   • For $x = 6$: $48 + 6 = 54$
   • For $x = 17$: $48 + 17 = 65$

   So, the values for $48 + x$ when $x = 0, 6, 17$ are $48, 54, 65$, respectively.

2. For the expression $12y$ when $y = 3, 6, 40$:

   • For $y = 3$: $12 \times 3 = 36$
   • For $y = 6$: $12 \times 6 = 72$
   • For $y = 40$: $12 \times 40 = 480$

   So, the values for $12y$ when $y = 3, 6, 40$ are $36, 72, 480$, respectively.

If you have any further questions or if there's anything else I can help you with, feel free to ask!