Question

- 12x-30x-48 = 36x+12x-9y 36+3x=-12+12y

Answer 1

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Answer 2

To solve the given system of linear equations, let's start by simplifying and organizing the equations:

Equation 1: -12x - 30x - 48 = 36x + 12x - 9y Simplify: -42x - 48 = 48x - 9y Rearrange: -42x - 48 - 48x = -9y -90x = -9y Divide both sides by -9: 10x = y ... (Equation A)

Equation 2: 36 + 3x = -12 + 12y Rearrange: 3x + 12 = 12y - 36 3x = 12y - 48 Divide both sides by 3: x = 4y - 16 ... (Equation B)

Now, let's substitute the value of y from Equation A into Equation B: x = 4(10x) - 16 x = 40x - 16

Now, isolate x on one side: 16 = 40x - x 16 = 39x x = 16/39

Now, substitute this value of x into Equation A to find y: 10x = y 10 * (16/39) = y y ≈ 4.1026 (approximately)

So, the solutions for x and y are approximately: x ≈ 0.4103 y ≈ 4.1026