Question

2sinx+1/sinx+4sin^2x+1/sin^2x=2

Answer 1

Ответ:

2

Пошаговое объяснение:

1 Артур + 1 Артур = 2 Артура

У него же две страницы, одна резервная:)

Answer 2

To solve the given trigonometric equation $2\sin(x) + \frac{1}{\sin(x)} + 4\sin^2(x) + \frac{1}{\sin^2(x)} = 2$, you can start by simplifying the equation.

Let's first rewrite the equation with a common denominator:

$2\sin(x) + \frac{1}{\sin(x)} + 4\sin^2(x) + \frac{1}{\sin^2(x)} = 2$

Multiply through by $\sin^2(x)$ to get rid of the fractions:

$2\sin^3(x) + \sin^2(x) + 4\sin^4(x) + 1 = 2\sin^2(x)$

Rearrange the equation and combine like terms:

$4\sin^4(x) + 2\sin^3(x) - \sin^2(x) - 2\sin^2(x) + 1 = 0$

Now, this equation is a quartic equation in terms of $\sin(x)$. Unfortunately, solving quartic equations generally involves more complex methods, and there might not be a simple algebraic solution in terms of familiar functions.

You could try numerical methods or graphing to find approximate solutions. Alternatively, if this equation came from a specific problem or context, there might be some trigonometric identities or simplifications that can be applied to make the solution more manageable. Without additional context or restrictions on the values of $x$, it's challenging to provide a specific solution.