Question

Camel has six cans of regular soda and 15 cans of diet soda he wants to create some identical refreshment tables that will operate do you ring the American football game he doesn’t want to have any soda left over what is the greatest

Answer 1

1) 6 = 2•3
15 = 3•5
НОД (6;5) = 3 - greatest common divisor
Получается, что верблюду надо накрыть 3 стола.
2) 6:3 = 2 банки обычной содовой на каждом столе.
3) 5:3 = 5 банки диетической соды на каждом столе.

Three tables, each with 2 cans of regular soda + 5 cans of diet soda:

Tables:
1. (2 cans of regular soda + 5 cans of diet soda)
2. (2 cans of regular soda + 5 cans of diet soda)
3. (2 cans of regular soda + 5 cans of diet soda)

2+2+2 = 6 cans of regular soda
5+5+5 = 15 cans of diet soda)

Answer 2

To create identical refreshment tables for the American football game without any soda left over, you need to find the greatest common divisor (GCD) of the number of regular soda cans (6) and the number of diet soda cans (15).

The GCD is the largest number that can evenly divide both 6 and 15 without leaving a remainder. In this case, the GCD of 6 and 15 is 3.

So, you can create 3 identical refreshment tables, each containing 2 cans of regular soda and 5 cans of diet soda, and you won't have any soda left over.