Question

1) 16a – 7a + 0,96 = 2,22; 2) 2,6x + 5,04 = 5,3; 3) 9,3 – 0,14x = 8,95; 4) 8,6x – 6,9x + 0,49 = 1.

Answer 1

Ответ:

Пошаговое объяснение:

Answer 2

To solve these equations, we need to isolate the variable (a or x) on one side of the equation. Here are the solutions for each equation:

1. 16a - 7a + 0.96 = 2.22

Combine like terms on the left side:

(16a - 7a) + 0.96 = 2.22 9a + 0.96 = 2.22

Now, subtract 0.96 from both sides to isolate 'a':

9a = 2.22 - 0.96 9a = 1.26

Finally, divide both sides by 9 to find the value of 'a':

a = 1.26 / 9 a = 0.14

So, the solution is a = 0.14.

2. 2.6x + 5.04 = 5.3

Subtract 5.04 from both sides:

2.6x = 5.3 - 5.04 2.6x = 0.26

Now, divide both sides by 2.6 to find the value of 'x':

x = 0.26 / 2.6 x = 0.1

So, the solution is x = 0.1.

3. 9.3 - 0.14x = 8.95

Subtract 9.3 from both sides:

-0.14x = 8.95 - 9.3 -0.14x = -0.35

Now, divide both sides by -0.14 to find the value of 'x':

x = -0.35 / -0.14 x = 2.5

So, the solution is x = 2.5.

4. 8.6x - 6.9x + 0.49 = 1

Combine like terms on the left side:

(8.6x - 6.9x) + 0.49 = 1 (8.6 - 6.9)x + 0.49 = 1 1.7x + 0.49 = 1

Now, subtract 0.49 from both sides:

1.7x = 1 - 0.49 1.7x = 0.51

Finally, divide both sides by 1.7 to find the value of 'x':

x = 0.51 / 1.7 x = 0.3

So, the solution is x = 0.3.