Question

Log по основанию 0.4× (2+sinπ/6)

Answer 1

Log(0,4)(2+sinπ/6)=log(0,4)((2+1/2)=
log(2/5)(5/2)=log(2/5)(2/5)^(-1)=-1

Answer 2

To evaluate the logarithm with base 0.4 of the expression (2 + sin(π/6)), you can use the formula:

log_b(x) = log_a(x) / log_a(b)

where b is the base, x is the value inside the logarithm, and a is any positive number other than 1.

Let's calculate it step by step:

Step 1: Calculate the value inside the logarithm (2 + sin(π/6)) = 2 + 0.5 = 2.5

Step 2: Calculate the logarithm of the value inside the logarithm with base 10 (or any other base) log(2.5) ≈ 0.39794 (rounded to five decimal places)

Step 3: Calculate the logarithm with base 0.4 using the formula mentioned above log_0.4(2.5) = log(2.5) / log(0.4) ≈ 0.39794 / (-0.39794) ≈ -1

So, the logarithm with base 0.4 of (2 + sin(π/6)) is approximately -1.