Question

3)(xy-2x+y)*3+2(2xy+3x-6y),если x=1 2/3,y=-5/6

Answer 1

$(xy-2x+y)*3+2(2xy+3x-6y)=3xy-6x+3y+4xy+6x-12y$
$=7xy-9y=y(7x-9)$
$-\frac{5}{6}(7*1 \frac{2}{3}-9)= -\frac{5}{6}(\frac{35-27}{3})=-\frac{5}{6}*\frac{8}{3}=-\frac{40}{18}=-2\frac{2}{9}$

Answer 2

To evaluate the expression $(xy-2x+y) \times 3 + 2(2xy+3x-6y)$ with the given values $x = \frac{1}{3}$ and $y = -\frac{5}{6}$, follow these steps:

1. Replace $x$ and $y$ in the expression with their respective values.
2. Perform the calculations according to the order of operations (PEMDAS/BODMAS).

Step 1: $(xy-2x+y) \times 3 + 2(2xy+3x-6y)$

Replace $x = \frac{1}{3}$ and $y = -\frac{5}{6}$:

$\left(\frac{1}{3} \times (-2) + \left(-\frac{5}{6}\right)\right) \times 3 + 2 \left(2 \times \frac{1}{3} + 3 \times \frac{1}{3} - 6 \times \left(-\frac{5}{6}\right)\right)$

Step 2: Now, perform the calculations inside the parentheses first:

$\left(-\frac{2}{3} - \frac{5}{6}\right) \times 3 + 2 \left(\frac{2}{3} + \frac{3}{3} + \frac{30}{6}\right)$

Next, simplify the expressions inside the parentheses further:

$\left(-\frac{4}{6} - \frac{5}{6}\right) \times 3 + 2 \left(\frac{2}{3} + 1 + \frac{30}{6}\right)$

Now, combine the fractions and perform the operations outside the parentheses:

$\left(-\frac{9}{6}\right) \times 3 + 2 \left(\frac{32}{6}\right)$

Multiply and add:

$-\frac{27}{6} + \frac{64}{6}$

Now, combine the fractions:

$\frac{37}{6}$

So, the value of the expression $(xy-2x+y) \times 3 + 2(2xy+3x-6y)$ with $x = \frac{1}{3}$ and $y = -\frac{5}{6}$ is $\frac{37}{6}$.