
Неравенства a)x <2;7. б)х_<8в)х <4 4/5


Ответы на вопрос

1)х={2,6 и все числа меньшие этого сисла }
2)х={8,7,6,5...}
3)х={4,7;4,6;4,5...}



To solve each inequality, let's find the value of "x" that satisfies the given conditions.
a) x < 2:
For this inequality, any value of "x" that is less than 2 would satisfy it. It forms an open interval on the number line. For example, x = 1 or x = 1.5 would satisfy this inequality.
b) x ≤ 8:
This inequality represents a closed interval, where "x" can be equal to 8. Any value of "x" that is less than or equal to 8 would satisfy the inequality. For example, x = 8, x = 7, or x = -3 would satisfy this inequality.
c) x < 4 4/5:
To solve this inequality, we first need to convert 4 4/5 to an improper fraction:
4 4/5 = (5 * 4 + 4) / 5 = 24 / 5
Now the inequality becomes:
x < 24/5
So any value of "x" that is less than 24/5 would satisfy this inequality. It forms an open interval on the number line. For example, x = 4, x = 2, or x = -1 would satisfy this inequality.


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