Question

Сума коренів рівняння 2x²+7x-3=0 дорівнює....а)-7б)-3.5в)3.5г)7

Answer 1

По теореме Виета:

x₁ + x₂ = -7/2 = -3,5

Ответ: б) -3,5

Answer 2

$2 x^{2} +7x-3=0$
$D=49+24=75$
$x_{1}= \frac{-7- \sqrt{75} }{4}$
$x_{2} = \frac{-7+ \sqrt{75} }{4}$
$\frac{-7- \sqrt{75} }{4}+\frac{-7+ \sqrt{75} }{4}=- \frac{14}{4} =-3.5$
Ответ: б)

Answer 3

To find the sum of the roots of the quadratic equation $ax^2 + bx + c = 0$, you can use the formula:

$$\text{Sum of roots} = \frac{-b}{a}$$

For the equation $2x^2 + 7x - 3 = 0$, the coefficient of $x^2$ is $a = 2$ and the coefficient of $x$ is $b = 7$. Plugging these values into the formula:

$$\text{Sum of roots} = \frac{-7}{2} = -3.5$$

So the correct answer is (в) $3.5$.