Question

3 ^корень 2x+6*3 ^корень 2x=21

Answer 1

3 ^корень 2x+6*3 ^корень 2x=21
Приведем подобные члены.
7*3^корень 2x=21
Разделим обе части уравнения на 7.
3^корень 2x=3
Представим в виде степени.
3^корень 2x=3¹
√2х=1
2х=1
Разделить обе части на 2.
х=1/2
х=0,5

Answer 2

To solve the equation $3\sqrt{2x} + 6\sqrt{2x} = 21$, follow these steps:

Step 1: Combine the square root terms on the left side of the equation.

$3\sqrt{2x} + 6\sqrt{2x} = 9\sqrt{2x}.$

Step 2: Rewrite the equation with the combined square root term.

$9\sqrt{2x} = 21.$

Step 3: Isolate the square root term by dividing both sides by 9.

$\sqrt{2x} = \frac{21}{9} = \frac{7}{3}.$

Step 4: To eliminate the square root, square both sides of the equation.

$(\sqrt{2x})^2 = \left(\frac{7}{3}\right)^2.$

Step 5: Solve for $x$.

$2x = \frac{49}{9}.$

Step 6: Finally, divide by 2 to get the value of $x$.

$x = \frac{49}{9 \cdot 2} = \frac{49}{18}.$

So, the value of $x$ that satisfies the equation is $x = \frac{49}{18}$.