Question

(3x+2y+z)/(4x-3y-z) если x/y/z=1/2/3

Answer 1

Если я правильно понимаю, то Х так относится к Y, как 1 к 2, и Х так относится к Z, как 1 к 3 => y=2x z=3x.

(3x+2y+z)/(4x-3y-z)=(3x+2*2x+3x)/(4x-3*(2x)-3x)=(3x+4x+3x)/(4x-6x-3x)=10x/(-5x)=-2

Answer 2

(3x+2y+z)/(4x-3y-z) = (3+4+3)/(4-6-3)=10/-5=-2

Ответ:-2

Answer 3

To find the value of the expression (3x + 2y + z) / (4x - 3y - z) when x/y/z = 1/2/3, we first need to substitute the values of x, y, and z into the expression.

Given: x/y/z = 1/2/3

We can rewrite this as: x = 1 * k, where k is a constant y = 2 * k z = 3 * k

Now let's substitute these values into the expression (3x + 2y + z) / (4x - 3y - z):

(3x + 2y + z) / (4x - 3y - z) = [3(1 * k) + 2(2 * k) + (3 * k)] / [4(1 * k) - 3(2 * k) - (3 * k)] = (3k + 4k + 3k) / (4k - 6k - 3k) = (10k) / (-5k) = -2

Therefore, the value of the expression (3x + 2y + z) / (4x - 3y - z) when x/y/z = 1/2/3 is -2.