Question

Sin2a - (Sina + cosa)²

Answer 1

sin2a+(sina-cosa)^2=sin2a+sin^2(a)-2sinacosa+cos^2(a)=sin2a+sin^2(a)-sin2a+cos^2(a)=1

Answer 2

Ответ:

Sin2a+(Sina-Cosa)^2=2*Sina*Cosa+(Sina)^2-2*Sina*Cosa+(Cosa)^2=(Sina)^2+(Cosa)^2=1

P.S.  ^2 значит в квадарате, т.е. (Sina)^2 это синус квадрат альфа и скобки ставить не нужно,   * это знак умножения

Пошаговое объяснение:

Answer 3

To simplify the expression, let's expand the second term and then combine like terms:

We know the identity: (sin(a) + cos(a))^2 = sin^2(a) + 2sin(a)cos(a) + cos^2(a).

Now, let's substitute this back into the original expression:

sin^2(a) - (sin(a) + cos(a))^2

= sin^2(a) - (sin^2(a) + 2sin(a)cos(a) + cos^2(a))

= sin^2(a) - sin^2(a) - 2sin(a)cos(a) - cos^2(a)

Since sin^2(a) - sin^2(a) cancels out, we get:

= -2sin(a)cos(a) - cos^2(a)

Now, we can use the identity: sin(2a) = 2sin(a)cos(a) to further simplify the expression:

= -sin(2a) - cos^2(a)

So, the simplified expression is -sin(2a) - cos^2(a).