Question

(y-7)(y+3)+(y-1)(y+5)=110​

Answer 1

Ответ:

y=-2 √17

y= 2 √17

Пошаговое объяснение:

y^2+3y-7y-21+y^2+5y-y-5=110

2y^2+0-26=110

2y^2=110+26

2y^2=136

y=-2 √17

y= 2 √17

Answer 2

To solve the equation $(y-7)(y+3)+(y-1)(y+5)=110$, you'll need to use the distributive property and then simplify the expression on the left-hand side before finding the value of $y$. Here's the step-by-step solution:

Step 1: Apply the distributive property. $(y-7)(y+3) + (y-1)(y+5) = 110$

Step 2: Expand the expressions. $y^2 + 3y - 7y - 21 + y^2 + 5y - y - 5 = 110$

Step 3: Combine like terms. Combine the terms with $y$ and the constant terms on the left-hand side. $2y^2 - 10 = 110$

Step 4: Move constant term to the right-hand side. $2y^2 = 110 + 10$

Step 5: Simplify the equation further. $2y^2 = 120$

Step 6: Divide by 2 to isolate $y^2$. $y^2 = \frac{120}{2}$

Step 7: Solve for $y$. $y^2 = 60$

To find $y$, take the square root of both sides. Remember that $y$ could be either positive or negative at this point.

$y = \pm \sqrt{60}$

Now, let's calculate the approximate values of $y$:

$y \approx \pm 7.746$

So, the solutions for $y$ are approximately $y \approx 7.746$ and $y \approx -7.746$.