Question

# 1 а)-1,5(3-4х)=-14,9+3,4хб)2,4(2х-3)-4(1,3х+2)=2,3х+3,7 в)1 1/2(2b+2,5)= 1/3b-0,5 #2-13,8:4 3/5+2 2/3(10,2-7,8)СРОЧНО ПОЖАЛУЙСТА​

Answer 1

Пошаговое объяснение:

#1

А) - 4,5+6х=-14,9+3,4х

6х*3,4х=-14,9+4,5

2,6х=-10,4

х=-4

Б)4,8х-7,2-5,2х-8=2,3х+3,7

-0,4х-15,2=2,3х+3,7

-0,4х-2,3х=3,7+15,2

-2,7х=18,9

х=-7

В) сложно чёт)

#2

Чуть позже напишу

Answer 2

Sure, let's solve the equations one by one:

#1a) Solve for x: -1.5(3 - 4x) = -14.9 + 3.4x

Step 1: Distribute the -1.5 on the left side of the equation: -4.5 + 6x = -14.9 + 3.4x

Step 2: Move all the x terms to one side of the equation and constants to the other side: 6x - 3.4x = -14.9 + 4.5

Step 3: Combine like terms: 2.6x = -10.4

Step 4: Solve for x: x = -10.4 / 2.6 x = -4

#1b) Solve for x: 2.4(2x - 3) - 4(1.3x + 2) = 2.3x + 3.7

Step 1: Distribute the constants on both sides of the equation: 4.8x - 7.2 - 5.2x - 8 = 2.3x + 3.7

Step 2: Move all the x terms to one side of the equation and constants to the other side: 4.8x - 5.2x - 2.3x = 3.7 + 7.2 + 8

Step 3: Combine like terms: -2.7x = 18.9

Step 4: Solve for x: x = 18.9 / -2.7 x = -7

#1c) Solve for b: 1 1/2(2b + 2.5) = 1/3b - 0.5

Step 1: Distribute the 1 1/2 on the left side of the equation: 3b + 3.75 = 1/3b - 0.5

Step 2: Move all the b terms to one side of the equation and constants to the other side: 3b - 1/3b = -0.5 - 3.75

Step 3: Combine like terms: (3 - 1/3)b = -4.25

Step 4: Solve for b: (8/3)b = -4.25

Step 5: Multiply by the reciprocal of (8/3) to isolate b: b = -4.25 * (3/8) b = -51/8 b = -6.375

#2) Solve the expression: -13.8 ÷ 4 + 3/5 + 2 2/3(10.2 - 7.8)

Step 1: Perform the operations inside the parentheses: 10.2 - 7.8 = 2.4

Step 2: Perform the multiplication: 2 2/3 * 2.4 = 2.666... ≈ 2.67

Step 3: Perform the division: -13.8 ÷ 4 = -3.45

Step 4: Add all the results: -3.45 + 3/5 + 2.67

Step 5: Convert the fraction 3/5 to a decimal: 3/5 = 0.6

Step 6: Add all the numbers together: -3.45 + 0.6 + 2.67 ≈ -0.18

The final result is approximately -0.18.

Please double-check the calculations to ensure accuracy. If you have any more questions or need further assistance, feel free to ask!