Question

2) sin^b - 1;3) sin^2f+ cos^2f + 1;​

Answer 1

$\boxed {sin^2\beta +cos^2\beta =1}\\\\\\2)\; \; sin^2\beta -1=cos^2\beta \\\\\\3)\; \; \underbrace{sin^2\varphi +cos^2\varphi }_{1}+1=1=1=2$

Answer 2

Let's simplify the expressions you provided:

2. sin^b - 1

The expression "sin^b" is ambiguous because it doesn't specify the value of 'b.' If 'b' is a specific number, please provide that value so that we can simplify the expression further.

3. sin^2f + cos^2f + 1

In trigonometry, the Pythagorean identity states that sin^2(x) + cos^2(x) = 1 for any angle 'x.' Therefore, applying this identity to the expression sin^2f + cos^2f, we can simplify it as:

sin^2f + cos^2f = 1

So, the simplified form of the expression sin^2f + cos^2f + 1 is just:

1 + 1 = 2

Therefore, sin^2f + cos^2f + 1 simplifies to 2.