Question

Укажите недостающие числа последовательности: 2/5; 4/15; ...; 8/25; ...; 12/35

Answer 1

2/5;4/15;6/20;8/25;10/30;12/35
В числителе по 2 прибавляешь а в знаменателе по 5

Answer 2

To find the missing numbers in the sequence, we need to observe the pattern in the given fractions. Let's analyze the numerators and denominators separately:

Numerators: 2, 4, ..., ?, 8, ?, 12 Denominators: 5, 15, ..., ?, 25, ?, 35

To identify the pattern, let's focus on the numerators first:

Numerators: 2, 4, ?, 8, ?, 12

The numerators seem to increase by 2 each time. So, the missing numerators are: 6 (2 + 2), and 10 (4 + 2).

Now, let's look at the denominators:

Denominators: 5, 15, ?, 25, ?, 35

The denominators do not follow a simple arithmetic sequence. However, we can notice that they are multiples of 5. To obtain the missing denominators, let's multiply the numerator by 5:

Denominator for 6: 6 * 5 = 30 Denominator for 10: 10 * 5 = 50

Now we have the complete sequence:

2/5; 4/15; 6/30; 8/25; 10/50; 12/35