Question

Х(x-3)-(x-5)(х+5)=(х+1)²​

Answer 1

Ответ: -8 и 3.

Пошаговое объяснение:

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Answer 2

Пошаговое объяснение:

x²-3x-(x²-25)=x²+1

x²-3x-x²+25=x²+1

-x²-3x+24=0

Answer 3

To solve the equation, let's first simplify it step by step:

1. Expand both sides of the equation: Left side: H(x-3) - (x-5)(x+5) = Hx - 3H - (x^2 - 25) Right side: (x+1)^2 = (x+1)(x+1) = x^2 + 2x + 1

2. Now, rewrite the equation with the simplifications: Hx - 3H - (x^2 - 25) = x^2 + 2x + 1

3. Move all terms to one side of the equation: Hx - 3H - x^2 + 25 = x^2 + 2x + 1

4. Combine like terms: Hx - x^2 - 3H + 25 = x^2 + 2x + 1

5. Now, bring all terms to one side to set the equation to zero: Hx - x^2 - 3H + 25 - x^2 - 2x - 1 = 0

6. Simplify further: -2x^2 + Hx - 2x - 3H + 24 = 0

The equation we have now is a quadratic equation in terms of 'x' with the coefficients 'H' and constants '3H - 24'. To solve for 'x', we need to specify the value of 'H' and then apply quadratic equation methods. If you have a specific value for 'H', you can plug it into the equation and proceed to solve for 'x'.

If you need further assistance or if you have the value of 'H', please provide it, and I can help you solve the equation completely.