Question

5(3х+2)=7+12у 4(х+у)+х=31

Answer 1

Ответ:

Пошаговое объяснение:

1.15х+10=7+12у

15х=7+12у-10

15х=-3+12у

х=-1/5+4/5у

2.4х+4у+х=31

5х+4у=31

5х=31-4у

х=31/5-4/5у

Answer 2

Ответ:

1.      15x+10=7+12y

        15x-12y=7-10

        3y= -3

        y=  -3 : 3

       y=  -1

2.     4x+4y+x=31

        5x+4y = 31

         5х=31-4у  

         х=31:5-4:5у

Пошаговое объяснение:

Answer 3

Let's solve the system of equations step by step.

Equation 1: 5(3x+2) = 7 + 12y

First, distribute the 5 to both terms inside the parentheses:

15x + 10 = 7 + 12y

Next, let's simplify the equation further:

15x = 7 + 12y - 10 15x = 12y - 3

Equation 2: 4(x+y) + x = 31

Let's simplify this equation as well:

4x + 4y + x = 31 5x + 4y = 31

Now we have a system of two equations:

15x = 12y - 3 5x + 4y = 31

To solve this system, we can use substitution or elimination method. Let's use the elimination method here.

Multiply the second equation by 3 to make the coefficients of x match:

15x + 12y = 93

Now we have two equations:

15x = 12y - 3 15x + 12y = 93

We can subtract the first equation from the second equation:

(15x + 12y) - (15x) = 93 - (-3) 12y = 96 y = 8

Now substitute the value of y back into the first equation:

15x = 12(8) - 3 15x = 96 - 3 15x = 93 x = 93/15 x = 31/5 or 6.2

Therefore, the solution to the system of equations is x = 6.2 and y = 8.