Question

4(5х+2)=10(2х-3)+152(7х-7)=7(2х-3)+7​

Answer 1

Ответ:

1) Утверждение ложно x∈∅

2) Утверждение верно x∈R

Пошаговое объяснение:

1) 4(5х+2)=10(2х-3)+15

  20x+8=20x-30+15

  8=-30+15

  8=-15

  Утверждение ложно

2) 2(7х-7)=7(2х-3)+7​

   14x-14=7(2x-3)+7

   -14=-21+7

   -14=-14

   Утверждение верно

Answer 2

Let's solve the equations step by step:

1. 4(5x + 2) = 10(2x - 3)

Distribute the numbers outside the parentheses:

20x + 8 = 20x - 30

Subtract 20x from both sides:

20x - 20x + 8 = -30

8 = -30

This equation has no solution because 8 cannot be equal to -30.

2. 152(7x - 7) = 7(2x - 3) + 7

Distribute the numbers outside the parentheses:

1064x - 1064 = 14x - 21 + 7

Subtract 14x from both sides:

1064x - 14x - 1064 = -21 + 7

1050x - 1064 = -14

Add 1064 to both sides:

1050x = 1050

Divide by 1050:

x = 1

3. 7(2x - 3) + 7 = 7

Distribute the numbers outside the parentheses:

14x - 21 + 7 = 7

Combine like terms:

14x - 14 = 7

Subtract 14 from both sides:

14x - 14 - 14 = 7 - 14

14x - 28 = -7

Add 28 to both sides:

14x = 21

Divide by 14:

x = 21 / 14

x = 3 / 2

So, the solutions for the given equations are:

1. No solution (the first equation)
2. x = 1 (the second equation)
3. x = 3/2 or 1.5 (the third equation)