Question

2 cos-x-cos x -1 > 0​

Answer 1

Ответ:

Ответ :x>0^x<2π/3, x>4π/3^x<2π

Пошаговое объяснение:

(2cos^2 x-cos(x))-1>0

X0=x1-1/10

(2cos^2 x-cos(x))-1>0

-1+(-cos(-1/10)+2cos^2(-1/10))>0

Тогда x<0

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Надеюсь я помогла

Answer 2

To solve the inequality 2cos(x) - cos(x) - 1 > 0, we can simplify it by combining like terms:

2cos(x) - cos(x) - 1 > 0 (cos(x) - 1) > 0

Now, we can solve for cos(x) - 1 > 0:

cos(x) - 1 > 0 cos(x) > 1

However, the range of values for cosine function is between -1 and 1. There is no solution for cos(x) > 1.

Therefore, the inequality 2cos(x) - cos(x) - 1 > 0 has no solution.