Question

Sin^2a+sin^2a*cos^2a+cos^4​

Answer 1

Ответ:

1

Пошаговое объяснение:

Разделим на cos^2a cos^2a+sin^2a+(sin^2a/cos^2a)=1/cos^2a 1+(sin^2a-1)/cos^2a=0 cos^2a+sin^2a-1=0 sin^2a+cos^2a=1, что и требовалось доказать

Answer 2

Let's simplify the expression step by step:

sin^2(a) + sin^2(a) * cos^2(a) + cos^4(a)

First, let's use the trigonometric identity: sin^2(a) + cos^2(a) = 1

sin^2(a) can be expressed as (1 - cos^2(a)), so we'll substitute that in:

(1 - cos^2(a)) + (1 - cos^2(a)) * cos^2(a) + cos^4(a)

Now, distribute the (1 - cos^2(a)) in the second term:

1 - cos^2(a) + cos^2(a) - cos^4(a) + cos^4(a)

Now, you can see that the cos^4(a) and -cos^4(a) terms cancel each other out:

1 - cos^2(a) + cos^2(a)

The -cos^2(a) and cos^2(a) terms also cancel out:

1

So, the simplified expression is 1.