Question

6х-34=4х 4с+23=67 2х+25=27 10а-23=17

Answer 1

Ответ:

1)

$6x - 3 4= 4x$

$6x - 4x = 34$

$2x = 34$

$x = 17$

2)

$4c + 23 = 67$

$4c = 67 - 23$

$4c = 44$

$c = 11$

3)

$2x + 2 5 = 27$

$2x = 27 - 25$

$2x = 2$

$x = 1$

4)

$10a - 23 = 17$

$10a = 17 + 23$

$10a = 40$

$a = 4$

Answer 2

Ответ:

1)17

2)11

3)1

4)4

Пошаговое объяснение:

1) 6x=4x+34

6x-4x=34

2x=34

x=34\2

x17

2)4c=67-23

4c=44

c=44\4

c=11

3)2x=27-25

2x=2

x=2\2

x=1

4)10a=17+23

10a=40

a=40\10

a=4

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Answer 3

It seems like you have a system of linear equations. Let's solve each equation one by one:

1. 6x - 34 = 4x To isolate x, you can subtract 4x from both sides of the equation: 6x - 4x - 34 = 4x - 4x 2x - 34 = 0

   Now, add 34 to both sides to solve for x: 2x - 34 + 34 = 0 + 34 2x = 34

   Finally, divide both sides by 2 to find the value of x: 2x/2 = 34/2 x = 17

2. 4c + 23 = 67 To isolate c, subtract 23 from both sides of the equation: 4c + 23 - 23 = 67 - 23 4c = 44

   Now, divide both sides by 4 to find the value of c: 4c/4 = 44/4 c = 11

3. 2x + 25 = 27 To isolate x, subtract 25 from both sides of the equation: 2x + 25 - 25 = 27 - 25 2x = 2

   Now, divide both sides by 2 to find the value of x: 2x/2 = 2/2 x = 1

4. 10a - 23 = 17 To isolate a, add 23 to both sides of the equation: 10a - 23 + 23 = 17 + 23 10a = 40

   Now, divide both sides by 10 to find the value of a: 10a/10 = 40/10 a = 4

So, the solutions to the equations are:

1. x = 17
2. c = 11
3. x = 1
4. a = 4