Question

2. А)8/29+14/29-17/29= Б)7 5/31-4 2/31+2 11/31= В)1-14/19= Г)7 3/7- 2 6/7= 3.в пятых классах 64 ученика,из них 3/16 составляют отличники.Сколько отличников в пятых классах? 4.мама приготовила вареники с творогом,а Коля съел 9 штук,что составляет 3/17 всех вареников.сколько вареников приготовила мама? 5.преобразуйте в смешанное число дробь: 1)15/6 2)39/12. 6.найдите все натуральные значения x,при которых верно неравенство 2 5/8 7.найдите все натуральные значения a,при которых одновременно выполняются условия:дробь a/4 будет неправильная,a дробь a/9 правильная.

Answer 1

Ответ:

2 задача: 1) 8/29+14/29-17/29=5/29  2)  7 5/31-4 2/31+2 11/31= 5 14/31

3)1-14/19=5/19

3 задача: 1) 64:16=4(отл)- в каждой части

2) 4*3=12(отл)

Ответ:12 отличников

4 задача: 1)9:3=3(вар) - 1/17 часть

2)3*17=51(вар)

Ответ: мама приготовила 51 варенникПравильные дроби: 1/2; 1/3; 1/4; 1/5; 1/6; 1/7

5 задача: 15/6 = 2 целых 3/6

39/12 = 3 целых 3/12

6 задача: Правильные дроби: 1/2; 1/3; 1/4; 1/5; 1/6; 1/7

Неправильные дроби:  7/2; 7/3;7/4; 7/5; 7/6

 Ответ: натуральные значения а: 2, 3, 4; 5; 6

Answer 2

Ответ:

всё пошагово

Пошаговое объяснение:

N.2

а)5/29

б)5 14/31

в)5/19

г)4 4/7

N.3

Решение:

64÷16×3=4×3=12

Ответ: 12 отличников.

N.4

Решение:

9÷3×17=3×17=51

Ответ: 51 вареник.

N.5

а)15/6=2 3/6=2 1/2

б)39/12=3 3/12=3 1/4

Сорян, дальше не знаю, прости :(

А в номере 3 и 4 не забудь написать краткую запись.

Answer 3

2) A) 8/29 + 14/29 - 17/29

To add or subtract fractions, the denominators must be the same. In this case, all the denominators are 29.

8/29 + 14/29 - 17/29 = (8 + 14 - 17)/29 = 5/29

So, the solution is 5/29.

B) 7 + 5/31 - 4 + 2/31 + 2 + 11/31

To add or subtract mixed numbers, add or subtract the whole numbers separately and the fractions separately.

7 + 5/31 - 4 + 2/31 + 2 + 11/31 = (7 - 4 + 2) + (5/31 + 2/31 + 11/31) = 5 + 18/31 = 5 18/31

So, the solution is 5 18/31.

C) 1 - 14/19

To subtract a fraction from a whole number, convert the whole number to a fraction with the same denominator as the fraction being subtracted.

1 - 14/19 = 19/19 - 14/19 = 5/19

So, the solution is 5/19.

D) 7 + 3/7 - 2 + 6/7

To add or subtract fractions, the denominators must be the same. In this case, all the denominators are 7.

7 + 3/7 - 2 + 6/7 = (7 - 2) + (3/7 + 6/7) = 5 + 9/7 = 6 2/7

So, the solution is 6 2/7.

3) In fifth grade, there are 64 students and 3/16 of them are excellent students.

To find the number of excellent students, multiply the total number of students by the fraction representing the excellent students.

Number of excellent students = 64 * 3/16 = 12

So, there are 12 excellent students in fifth grade.

4) Kolya ate 9 dumplings, which is 3/17 of all the dumplings.

To find the total number of dumplings, divide the number of dumplings Kolya ate by the fraction representing the dumplings.

Total number of dumplings = 9 / (3/17) = 9 * (17/3) = 51

So, the mother prepared 51 dumplings.

5) Convert the given fractions into mixed numbers.

1) 15/6 = 2 3/6 = 2 1/2

So, the mixed number form of 15/6 is 2 1/2.

2) 39/12 = 3 3/12 = 3 1/4

So, the mixed number form of 39/12 is 3 1/4.

6) Find all natural values of x that satisfy the inequality 2 5/8 + 7.

To solve the inequality, find the common denominator and add the mixed number with the whole number.

2 5/8 + 7 = 23/8 + 7 = 23/8 + 56/8 = 79/8

The inequality states that the expression must be greater than 7.

So, 79/8 > 7

To convert this inequality into mixed number form, divide the numerator by the denominator.

79/8 = 9 7/8

So, all natural values of x that satisfy the inequality are x > 9 7/8.

7) Find all natural values of a that simultaneously satisfy the conditions: the fraction a/4 will be improper and the fraction a/9 will be proper.

An improper fraction is when the numerator is greater than the denominator. A proper fraction is when the numerator is less than the denominator.

To satisfy the first condition, a/4 > 1. To satisfy the second condition, a/9 < 1.

To find the values of a, consider the multiples of 4 and 9.

Multiples of 4: 4, 8, 12, 16, 20, 24, 28, 32, ... Multiples of 9: 9, 18, 27, 36, 45, 54, 63, ...

From the multiples of 4, we can see that a must be greater than or equal to 5 to satisfy the first condition. From the multiples of 9, we can see that a must be less than or equal to 8 to satisfy the second condition.

So, the natural values of a that satisfy both conditions are 5, 6, 7, and 8.