Question

ДОМАШНЕЕ ЗАДАНИЕ 10 Реши задачу с помощью уравнения. Две снегоуборочные машины одновременно выехали в 8 утра и поехали в одном направлении. В 11 чутра расстояние меж- ду ними было 6 км. С какой скоростью двигалась первая ма- шина, если скорость второй машины 30 км/ч?​

Answer 1

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Answer 2

Problem Analysis

We are given that two snowplows started simultaneously at 8 am and traveled in the same direction. At 11 am, the distance between them was 6 km. We are also given that the second snowplow was traveling at a speed of 30 km/h. We need to find the speed of the first snowplow.

Solution

Let's assume the speed of the first snowplow is v km/h.

We can use the formula: distance = speed × time to solve this problem.

From 8 am to 11 am, a total of 3 hours have passed.

The distance covered by the second snowplow in 3 hours is: distance = speed × time = 30 km/h × 3 h = 90 km.

Since the distance between the two snowplows at 11 am was 6 km, we can set up the following equation:

distance covered by the first snowplow = total distance - distance covered by the second snowplow

distance covered by the first snowplow = 6 km

total distance = distance covered by the first snowplow + distance covered by the second snowplow

total distance = 6 km + 90 km = 96 km

Now, we can use the formula distance = speed × time for the first snowplow:

6 km = v km/h × 3 h

Simplifying the equation, we get:

v km/h = 6 km / 3 h = 2 km/h

Therefore, the speed of the first snowplow is 2 km/h.

Answer

The first snowplow was moving at a speed of 2 km/h.

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