Question

На трьох полицях стояло 122 книги, причому на першій полиці було на 6 книжок більше ніж на другій, а на третій-у 2 рази більш ніж на другій. Скільки книжок стояло на кожній полиці?

Answer 1

Відповідь:

На першій 35 на другій 29 на третій 58

Покрокове пояснення:

Припустимо що перша полиця це х+6 книжок, друга х книжок, а третя 2х книжок, Отже складемо рівняння

2х+х+х+6=122

4х=122-6

4х=116

х=29к. (друга полиця)

29+6=35к.(перша полиця)

29*2=58к.(третя полиця)

Answer 2

Solution:

Let's solve this step by step.

Let's assume the number of books on the second shelf is x.

According to the given information: - The number of books on the first shelf is 6 more than the number on the second shelf. - The number of books on the third shelf is 2 times the number on the second shelf.

So, we can express the number of books on the first and third shelves in terms of x.

The number of books on the first shelf = x + 6 The number of books on the third shelf = 2x

Now, we know that the total number of books on all three shelves is 122. We can use this information to form an equation.

The total number of books = x + (x + 6) + 2x = 122

Solving for x will give us the number of books on the second shelf. Then we can find the number of books on the first and third shelves.

Let's solve for x.

4x + 6 = 122 4x = 116 x = 29

So, the number of books on each shelf is: - First shelf: x + 6 = 29 + 6 = 35 books - Second shelf: x = 29 books - Third shelf: 2x = 2 * 29 = 58 books

Therefore, there were 35 books on the first shelf, 29 books on the second shelf, and 58 books on the third shelf.