Question

Найдите углы треугольника ABC,если угол А : угол B : угол C =1:2:6 (чтобы было дано) ПОЖАЛУЙСТА

Answer 1

Ответ:

20°  40°   120°

Объяснение:

Дано: ΔАВС; ∠А:∠В:∠С=1:2:6. Найти ∠А, ∠В, ∠С.

Найдем коэффициент пропорциональности х из уравнения

х+2х+6х=180

9х=180

х=20

∠А=20°, ∠В=20*2=40°, ∠С=20*6=120°

Answer 2

Finding the angles of triangle ABC

To find the angles of triangle ABC, we are given that the ratio of angle A to angle B to angle C is 1:2:6.

Let's denote the measure of angle A as x. Then, the measure of angle B would be 2x, and the measure of angle C would be 6x.

According to the given ratio, we have:

Angle A : Angle B : Angle C = 1 : 2 : 6

So, we can write the equation:

x : 2x : 6x = 1 : 2 : 6

To solve this equation, we can set up the following proportion:

x/1 = 2x/2 = 6x/6

Simplifying the proportions, we get:

x = 2x = 6x

Since all three proportions are equal, we can choose any value for x. Let's choose x = 1 for simplicity.

Therefore, the measure of angle A is 1 degree, the measure of angle B is 2 degrees, and the measure of angle C is 6 degrees.

In summary, the angles of triangle ABC are as follows: - Angle A = 1 degree - Angle B = 2 degrees - Angle C = 6 degrees

Please let me know if there's anything else I can help you with!