Question

Средняя линия трапеции равна 15 см. Найти основания трапеции, если одно из них на 8 см меньше другого.

Answer 1

M=1/2a+b
Пусть a = x, b = x-8
15 = 1/2(x+(x-8))  
15=1/2*2х-8
Решаем пропорцией: 
2х-8=30
2х=22
х=11 - меньшее основание
Большее основание = 11+8=19

Answer 2

1 основа - Х
2 основа - Х+8
(Х+Х+8)/2=15
2Х+8=30
2Х=22
Х=22/2
Х=11
1 основа - 11см
2 основа - 11+8=19см

Answer 3

Finding the bases of a trapezoid

To find the bases of a trapezoid when one base is 8 cm smaller than the other, we can use the information that the average of the bases is 15 cm.

Let's assume that one base of the trapezoid is x cm. Since the other base is 8 cm smaller, the second base can be represented as (x - 8) cm.

The average of the bases is given as 15 cm, so we can set up the following equation:

(x + (x - 8)) / 2 = 15

Simplifying the equation, we have:

(2x - 8) / 2 = 15

Now, we can solve for x:

2x - 8 = 30

2x = 38

x = 19

Therefore, one base of the trapezoid is 19 cm, and the other base is (19 - 8) = 11 cm.

So, the bases of the trapezoid are 19 cm and 11 cm.