Question

В треугольнике abc угол с равен 90 ac 6 bc 2 корень из 7 найти cos a СРОЧНО

Answer 1

Ответ:

0,75

Объяснение:

• Косинус острого угла прямоугольного треугольника равен отношению прилежащего катета к гипотенузе.

$\Rightarrow cos (A) = \dfrac{AC}{AB}$

Найдём AB по теореме Пифагора:

$AB^2 = AC^2 + BC^2 = 6^2+ (2\sqrt{7} )^2= 36 + 28 = 64$

$AB = \sqrt{64} = 8$ см

$\Rightarrow cos (A) = \dfrac{6}{8} = \dfrac{6 \cdot 125}{8 \cdot 125} = \dfrac{750}{1000} = 0,75$

Answer 2

Solution for Finding cos(a) in Triangle ABC

To find cos(a) in triangle ABC, where angle C is 90 degrees, AC = 6, and BC = 2√7, we can use the cosine function, which is defined as the ratio of the length of the adjacent side to the length of the hypotenuse in a right-angled triangle.

Using the given information: - Angle C: 90 degrees - Side AC: 6 - Side BC: 2√7

We can use the cosine function to find cos(a).

Using the Cosine Function

The cosine function is defined as: cos(a) = adjacent side / hypotenuse

In this case, the adjacent side to angle A is BC, and the hypotenuse is AC.

Calculating cos(a)

Using the given values: - Adjacent side (BC): 2√7 - Hypotenuse (AC): 6

We can calculate cos(a) as: cos(a) = BC / AC

Substituting the given values: cos(a) = (2√7) / 6

Final Result

After calculating the above expression, we find that: cos(a) ≈ 0.4714

Therefore, cos(a) ≈ 0.4714.