Question

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Answer 1

$\dfrac{2e^{i\frac{\pi}{2}}\cdot e^{20\pi i}}{e^{\frac{4\pi}{3}i}}=2e^{i\left(\frac{\pi}{2}+20\pi-\frac{4\pi}{3}\right)}=2e^{i\frac{115}{6}\pi}=2(\cos\frac{115\pi}{6}+i\sin \frac{115\pi}{6})=\\ \\ \\ =2\cdot \left(-\frac{\sqrt{3}}{2}-i\cdot \frac{1}{2}\right)=-\sqrt{3}-i$