Question

Решите уравнение плиз

Answer 1

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Answer 2

OДЗ: х≠3,-3.
$\frac{2x-2}{x+3}- \frac{18}{x^2-9}= \frac{x-6}{x-3}\\ \frac{2x-2}{x+3}- \frac{18}{(x-3)(x+3)}= \frac{x-6}{x-3}\\ (x-3)(x+3)* \frac{2x-2}{x+3}-(x-3)(x+3)* \frac{18}{(x-3)(x+3)}=\\=(x-3)(x+3)* \frac{x-6}{x-3}\\ (2x-2)(x-3)-18=(x+3)(x-6)\\ 2x^2-6x-2x+6-18=x^2-6x+3x-18\\ 2x^2-8x+6=x^2-3x\\ 2x^2-8x+6-x^2+3x=0\\ x^2-5x+6=0\\ x_1*x_2=6\\ x_1+x_2=5\\ x_1=2\\ x_2=3(ne//udovletvorayet).\\ OTBET: x=2.$