Question

РЕШИТЕ СИСТЕМУ УРАВНЕНИЙ! ДАМ 20 БАЛЛОВ

Answer 1

$\left \{ {{x^{2}-y=-2} \atop {2x+y=2}} \right.\\ y = 2-2x\\ x^{2}-(2-2x)=-2\\ x^{2}-2+2x+2=0\\ x^{2}+2x=0\\ x(x+2)=0\\ x_{1} = 0, x_{2}=-2\\ y_{1} = 2 - 2x_{1} = 2-0=2\\ y_{2}=2-2x_{2}=2-4=-2$