Question

Помогите упростить выражение

Answer 1

$\frac{2x}{x^2-1}:(\frac{1}{x^2+2x+1}-\frac{1}{1-x^2})=\frac{2x}{x^2-1}:(\frac{1}{(x+1)^2}-\frac{1}{(1-x)(1+x)})=\frac{2x}{x^2-1}:\frac{1-x-(x+1)}{(1-x)(x+1)^2}=\frac{2x}{x^2-1}:\frac{1-x-x-1}{(1-x)(x+1)^2}=\frac{2x}{x^2-1}:\frac{-2x}{(1-x)(x+1)^2}=-\frac{2x}{(x-1)(x+1)}:\frac{(1-x)(x+1)^2}{2x}=-\frac{1}{x-1}*(-(x-1))(x+1)=-(-(x+1))=-(-x-1)=x+1$