Question

Помоги пожалуйста в задаче В первой корзине в 2 раза меньше яблок,чем во второй.Когда из второй корзины переложили в первую 14 яблок, то в обеих корзинах яблок стало поровну.Сколько яблок было в каждой корзине первоначально?

Answer 1

было:

в первой корзине х

во второй 2х

стало:

в первой корзине х+14

во второй 2х-14

составим уравнение

2х-14=х+14

2х-х=14+14

х=28 было в первой корзине

28*2= 56 было во второй корзине

Answer 2

Problem Analysis

We are given two baskets of apples, and the number of apples in the first basket is two times less than the number of apples in the second basket. When 14 apples are transferred from the second basket to the first basket, the number of apples becomes equal in both baskets. We need to find the initial number of apples in each basket.

Solution

Let's assume the initial number of apples in the second basket is x. According to the problem, the number of apples in the first basket is two times less than the number of apples in the second basket, so the initial number of apples in the first basket is x/2.

When 14 apples are transferred from the second basket to the first basket, the number of apples becomes equal in both baskets. This means that the first basket now has x/2 + 14 apples, and the second basket has x - 14 apples.

Since the number of apples is now equal in both baskets, we can set up the following equation:

x/2 + 14 = x - 14

To solve this equation, we can multiply both sides by 2 to eliminate the fraction:

x + 28 = 2x - 28

Next, we can subtract x from both sides:

28 = x - 28

Finally, we can add 28 to both sides:

x = 56

Therefore, the initial number of apples in the second basket is 56, and the initial number of apples in the first basket is 56/2 = 28.

Answer

The initial number of apples in each basket was: - First basket: 28 apples - Second basket: 56 apples