Question

1) 2) 3)

Answer 1

1)
log(6) (x^2-5x)>1
log(6) (x^2-5x)>log(6) 6
x^2-5x>6
x^2-5x-6>0
дискриминант и находим отрезки
ОДЗ
x^2-5x>0
X(x-5)>0
-бесконечности до 0 и от 5 до +бесконечности
объеденяем этот отрезок с отрезком уранения x^2-5x-6>0 и выходит ответ
2)
log(4/10)((3x+1)/(x-2))>=1
log(4/10)((3x+1)/(x-2))>=log(4/10)(4/10)
(3x+1)/(x-2)>=4/10
30x+10>=4x-8
26x>=-18
x>=-18/26
ОДЗ
(3x+1)/(x-2)>0
(3x+1)*(x-2)>0       (подставляем * вместо / потому что знаки (одинаковые)сокрашаются)
находим отрезок
объеденяем и все
3)
x^(3 log(2)(x+1))<=16
x^(log(2)((x+1)^3))<=x^(log(x)16)
log(2)(x+1)^3<=log(x)16
ОДЗ
x+1>0
x>-1
x>0
x<>1
f дальше забыл как делать(если хочеш удали решение)

Answer 2

1) What is the solution to the equation (8x-3)/7 - (3x+1)/10 = 2?

To find the solution to the equation (8x-3)/7 - (3x+1)/10 = 2, we can follow these steps:

1. Multiply both sides of the equation by the least common denominator (LCD) of 7 and 10, which is 70, to eliminate the fractions. 2. Simplify the equation and solve for x.

The solution to the equation is x = 11/13.

Here's the step-by-step solution:

(8x-3)/7 - (3x+1)/10 = 2

Multiply both sides by the LCD (70):

70 * [(8x-3)/7 - (3x+1)/10] = 70 * 2

10 * (8x-3) - 7 * (3x+1) = 140

80x - 30 - 21x - 7 = 140

59x - 37 = 140

59x = 140 + 37

59x = 177

x = 177/59

x = 11/13

So, the solution to the equation (8x-3)/7 - (3x+1)/10 = 2 is x = 11/13.