Question

Решите уравнение за 7 класс (х 2 степень+5х)-х(х-5)=0срочно пожалуйста завтра уже проверять будут завтра помогите срочно

Answer 1

(x^2+5x)-x(x+5)=0
x^2+5x-(x^2-5x)=0
x^2+5x-x^2+5x=0
10x=0
x=0

Answer 2

Вводим замену 4x-1=t;3t²+t=0;t(3t+1)=0;t=0;t=-1/3; x₁=1/4;х₂=1/6.

Answer 3

Solving the Equation

To solve the equation (x + 2)^5x - x(x - 5) = 0, we can follow these steps:

Step 1: Expand the equation and simplify it as much as possible.

Step 2: Factorize the equation.

Step 3: Solve for the values of x that make the equation true.

Let's go through each step in detail.

Step 1: Expand and Simplify the Equation

Expanding the equation, we get:

(x + 2) * (x + 2) * (x + 2) * (x + 2) * (x + 2) * x - x(x - 5) = 0

Simplifying further:

(x + 2)^5 * x - x^2 + 5x = 0

Step 2: Factorize the Equation

To factorize the equation, we can look for common factors among the terms. In this case, we can factor out an x:

x * [(x + 2)^5 - x + 5] = 0

Now we have two factors: x and [(x + 2)^5 - x + 5].

Step 3: Solve for x

To find the values of x that make the equation true, we need to solve each factor separately.

First, let's solve the factor x = 0. This means that x can be equal to 0.

Next, let's solve the factor [(x + 2)^5 - x + 5] = 0. Unfortunately, this equation cannot be easily solved algebraically. We can use numerical methods or graphing to approximate the solutions.

Based on the information provided, it seems that the equation you provided may not have a simple algebraic solution. It would be best to use numerical methods or consult with your teacher for further guidance.

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