
Построить график функции y=-3x+3


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Graph of the Function y = -3x + 3
To graph the function y = -3x + 3, we can use the slope-intercept form of a linear equation, which is y = mx + b. In this equation, m represents the slope of the line, and b represents the y-intercept.
For the given function, the slope (m) is -3, and the y-intercept (b) is 3.
To plot the graph, we can start by plotting the y-intercept, which is the point (0, 3). From there, we can use the slope to find additional points and draw a straight line through them.
Let's calculate a few more points to plot on the graph:
When x = 1: y = -3(1) + 3 = 0 So, the point (1, 0) is on the graph.
When x = 2: y = -3(2) + 3 = -3 So, the point (2, -3) is on the graph.
When x = -1: y = -3(-1) + 3 = 6 So, the point (-1, 6) is on the graph.
Now, let's plot these points and draw the line:

The graph of the function y = -3x + 3 is a straight line with a slope of -3 and a y-intercept of 3. It passes through the points (0, 3), (1, 0), (2, -3), and (-1, 6).
I hope this helps! Let me know if you have any further questions.


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