Question

Дополните запись чтобы равенство стало верным 1) 9а-12а 2) 4 3х=2 3 (степени) 3) 1 2=1 (степень)

Answer 1

2)4³x=2³,
64x=8,
x=0.125(т.к мы 8:64),
Проверка:64×0.125=8;
Ответ:0.125.
3)1²=1,
1=1;
Проверка:1×1=1,
Ответ:1.

Answer 2

To make the equations true, let's solve each one step by step:

1) 9а - 12а

The equation can be simplified by combining like terms. The terms "9а" and "-12а" have the same variable "а". To combine them, we subtract the coefficients:

9а - 12а = -3а

So, the equation becomes -3а.

2) 4 + 3х = 2 + 3^(степени)

Here, we have an equation with variables. To solve for "х", we'll isolate it on one side of the equation. Let's go step by step:

First, simplify the right side of the equation: 3^(степени) means "3 raised to the power of something." Since we don't know the specific exponent, we can't simplify it further at this point.

Now, let's simplify the left side of the equation by combining like terms:

4 + 3х = 2 + 3^(степени)

Next, let's isolate "х". We'll start by subtracting 2 from both sides of the equation:

4 + 3х - 2 = 2 + 3^(степени) - 2

This simplifies to:

2 + 3х = 3^(степени)

Now, let's subtract 2 from both sides:

2 + 3х - 2 = 3^(степени) - 2

The 2's cancel out, leaving us with:

3х = 3^(степени) - 2

To solve for "х", we would need to know the specific exponent for the right side of the equation, as "3^(степени)" could represent any power of 3.

3) 1 + 2 = 1^(степень)

This equation involves exponents as well. Similar to the previous equation, we would need to know the specific exponent to solve it accurately.

In summary, to make the equations true, we simplified the first equation to -3а. For the second and third equations, the specific exponents are needed to solve for "х" and the right side of the equation, respectively.