Question

Полное решение!11!Решите неравенство:

Answer 1

$\frac{x^2-7x+6}{x-2} \leq 0\\\\ x^2-7x+6=(x-1)(x-6)\\\\\ \frac{(x-1)(x-6)}{x-2} \leq 0\\\\ x \neq 2$
$1) \left \{ {{(x-1)(x-6) \geq 0} \atop {x-2<0}} \right. \\\\ 2) \left \{ {{(x-1)(x-6) \leq 0 } \atop {x-2>0}} \rigaht.$
Первое неравенство 
$1) \left \{ {{(x-1)(x-6) \geq 0} \atop {x-2<0}} \right. \\\\ 1) \left \{ {{x \leq 1 \ ; \ x \geq 6} \atop {x<2}} \right. \\\\ 1) \left \{ {{x \geq 1 ; x \leq 6} \atop {x<2}} \right.$
 Получаем решение 
$x \in (\infty;1)$

Второе неравенство  
$\left \{ {{(x-1)(x-6) \leq 0 } \atop {x>2}} \right. \\\\ \left \{ {{x \leq 1 ; \ \ x \geq 6} \atop {x>2}} \right. \\\\ \left \{ {{x \geq 1; x \leq 6} \atop {x<2}} \right.$ 
 Получаем решение 
 $> Объединяя    <img src=$

Answer 2

Solving the Inequality

To solve the given inequality, we need to determine the values of the variable that satisfy the inequality. Unfortunately, the inequality itself is not provided in the question. Could you please provide the inequality so that I can assist you further?