Question

Решите неравенство 3(2х-3)+4х< -10

Answer 1

$3(2x-3)+4x\ \textless \ -10 \\ 6x-9+4x\ \textless \ -10 \\ 10x\ \textless \ -1 \\ x\ \textless \ -\frac{1}{10} \\ x\in (-\infty;- \frac{1}{10} )$

Answer 2

6х-9+4х<-10
10x<-10+9
10x<-1
x<-0,1

Answer 3

3(2x-3) + 4x < -10 6x - 9 + 4x < -10 10x - 9 < -10 10x < -1 x < -1/10

Ответ: x < -1/10