Question

A=a²-3a+2, B=2a²+3a-1Решите выражениеA·(-B)

Answer 1

А=а^2-3а+2 Д=(-3)^2-4*1*2=1 A1=3+1/2=4 A2=3-1/2=1

Answer 2

I can help you with your math problem. To solve the expression A·(-B), you need to multiply A and B, and then change the sign of the result. Here are the steps:

- First, expand A and B using the distributive property: $$A = a^2 - 3a + 2 = (a - 1)(a - 2)$$ and $$B = 2a^2 + 3a - 1 = (2a - 1)(a + 1)$$ - Next, multiply A and B using the FOIL method: $$A \cdot B = (a - 1)(a - 2)(2a - 1)(a + 1) = (2a^2 - 5a + 2)(a^2 - a - 2)$$ - Then, expand the product using the distributive property again: $$A \cdot B = 2a^4 - 9a^3 + 5a^2 + 4a - 4$$ - Finally, change the sign of the result to get A·(-B): $$A \cdot (-B) = -2a^4 + 9a^3 - 5a^2 - 4a + 4$$

This is the final answer. I hope this helps.Ответь+подробно.+A=a²-3a+2,+B=2a²+3a-1Решите+выражениеA·(-B)