Question

Два пешехода вышли одновременно навстречу друг другу из двух деревень и через 2 часа встретились. Расстояние между деревнями 18км. Найти скорость пешеходов, если один шел быстрее другого на 1 км/ч.

Answer 1

Пусть х км/ч - скорость одного пешехода.Тогда скорость другого - (х+1)км/ч. Т.к V=S:t ,можем составить уравнение:
х+(х+1)=18:2
2х+1=9
2х=8
х=4 - скорость одного пешехода
х+1=5 - скорость второго пешехода

Answer 2

1) 5+4=9 (км/ч) - скорость сближения пешеходов

2) 18:9=2 (часа) - время, через которое они встретятсяНапишите в ответе здесь

Answer 3

Problem Analysis

Two pedestrians start walking towards each other from two different villages and meet after 2 hours. The distance between the villages is 18 km. One pedestrian walks 1 km/h faster than the other. We need to find the speed of each pedestrian.

Solution

Let's assume the speed of the slower pedestrian is x km/h. Then the speed of the faster pedestrian will be x + 1 km/h.

We can use the formula distance = speed × time to calculate the distance covered by each pedestrian.

The slower pedestrian covers a distance of x × 2 km in 2 hours, and the faster pedestrian covers a distance of (x + 1) × 2 km in 2 hours.

Since they meet after 2 hours, the sum of the distances covered by both pedestrians should be equal to the total distance between the villages, which is 18 km.

So, we can set up the following equation:

x × 2 + (x + 1) × 2 = 18

Simplifying the equation:

2x + 2x + 2 = 18

4x + 2 = 18

4x = 16

x = 4

Therefore, the speed of the slower pedestrian is 4 km/h and the speed of the faster pedestrian is 5 km/h.

Answer

The speed of the slower pedestrian is 4 km/h and the speed of the faster pedestrian is 5 km/h.