Question

Помогите, пожалуйста решить задачу уравнением. Учащиеся трех седьмых классов поехали на экскурсию в трех автобусах. В третьем автобусе сидело на 5 учеников меньше, чем в первом, и на 4 человека больше, чем во втором. Сколько учеников сидело в каждом автобусе, если всего на экскурсию поехали 67 учеников?

Answer 1

Пусть х -третьем автобусе
х+5 - в первом автобусе
х-4 - во втором автобусе
всего 67

х+х+5+х-4=67
3х+5-4=67
3х+1=67
3х=67-1
3х=66
х=66:3
х=22 ученика сидело в третьем автобусе
22+5=27 учеников сидело в первом автобусе
22-4=18 учеников сидело во втором автобусе

Answer 2

Problem Analysis

We are given that three groups of students from different seventh-grade classes went on a trip in three buses. The third bus had 5 students fewer than the first bus and 4 students more than the second bus. We need to determine the number of students in each bus, given that a total of 67 students went on the trip.

Solution

Let's assume the number of students in the first bus is x. According to the problem, the number of students in the third bus is 5 fewer than the first bus, which is x - 5. The number of students in the second bus is 4 fewer than the third bus, which is (x - 5) - 4.

We know that the total number of students on the trip is 67. So we can set up the equation:

x + (x - 5) + ((x - 5) - 4) = 67

Now we can solve this equation to find the value of x.

Calculation

x + (x - 5) + ((x - 5) - 4) = 67

Simplifying the equation:

x + x - 5 + x - 5 - 4 = 67

Combining like terms:

3x - 14 = 67

Adding 14 to both sides:

3x = 81

Dividing both sides by 3:

x = 27

Now we can find the number of students in each bus:

First bus: x = 27 students Second bus: (x - 5) = 27 - 5 = 22 students Third bus: ((x - 5) - 4) = (27 - 5) - 4 = 18 students

Answer

Therefore, there were 27 students in the first bus, 22 students in the second bus, and 18 students in the third bus.