Question

Из четырех пожертвователей второй дал вдвое больше первого, третий-втрое больше второго, четвертый-вчетверо больше третьего, а все вместе дали 132 рупий. Сколько дал каждый?

Answer 1

Пусть x дал первый, тогда второй 2x, третий 3*2x, четвертый 4*3*2x

x+2x+6x+24x=132
33x=132
x=4
4 рупия дал первый
2*4=16-второй
6*4=24-третий
24*4=96-четвертый

Answer 2

Solution:

Let's solve this step by step.

Let's assume the first donor gave x rupees.

The second donor gave 2x rupees.

The third donor gave 3x rupees.

The fourth donor gave 4x rupees.

According to the given information, the total amount donated is 132 rupees.

So, we can form the equation: x + 2x + 3x + 4x = 132.

Solving for x will give us the amount each donor contributed.

Calculation:

x + 2x + 3x + 4x = 132

10x = 132

x = 13.2

Now, we can find the amount each donor gave:

- The first donor gave 13.2 rupees. - The second donor gave 2 * 13.2 = 26.4 rupees. - The third donor gave 3 * 13.2 = 39.6 rupees. - The fourth donor gave 4 * 13.2 = 52.8 rupees.

So, each donor gave the following amounts: - First donor: 13.2 rupees - Second donor: 26.4 rupees - Third donor: 39.6 rupees - Fourth donor: 52.8 rupees

This is the solution to the given problem.

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