Question

Решите пожалуйста)(а-2)/(а+1)-5/(а+1) в квадрате : 5/(а в квадрате-1)-(3а+2)/(а+1) Ответ должен получится-3

Answer 1

(a-2)/(a+1)-(3a+2)/(a+1)-5*(a^2-1)/5(a+1)^2=(a-2-a+1-3a-2)/(a+1)=-3(a+1)/(a+1)=-3

Answer 2

Solving the Equation

To solve the given equation, we'll follow these steps:

1. Combine Like Terms: Combine the terms with the same denominator. 2. Factorize: Factorize the resulting expression. 3. Simplify: Simplify the expression to solve for the variable.

Step 1: Combine Like Terms

The given expression is: ((a-2)/(a+1)) - (5/(a+1)) + (a^2) / (5/(a^2-1)) - ((3a+2)/(a+1))

Combining the terms with the same denominator, we get: ((a-2-5+a^2-3a-2)/(a+1)) + (a^2) / (5/(a^2-1))

Simplifying, we get: ((a^2 - 3a - 7)/(a+1)) + (a^2) / (5/(a^2-1))

Step 2: Factorize

We'll factorize the expression (a^2 - 3a - 7).

Step 3: Simplify

After factorizing, we'll simplify the expression to solve for the variable.

Let's proceed with factorizing the expression (a^2 - 3a - 7).