Question

Решите уравнение (2x-1) в квадрате -(2x-2)(2x-2)=38

Answer 1

(2x-1)^2-(2x-2)(2x-2)=38
4x^2-4x+1-4x^2+8x-4=38
4x=38-1+4
4x=41
x=41/4
x=10,25

Ответ:  x = 10,25

Answer 2

I can help you with solving equations. Here is the solution for your equation:

(2x-1)^2-(2x-2)^2=38

First, we expand the brackets using the formula $(a-b)^2=a^2-2ab+b^2$:

4x^2-4x+1-4x^2+8x-4=38

Then, we simplify the equation by collecting like terms:

4x-3=38

Finally, we isolate x by adding 3 to both sides and dividing by 4:

x=\frac{41}{4}

Therefore, the solution is $x=\frac{41}{4}$. I hope this helps.Ответь+подробно.+Решите+уравнение+(2x-1)+в+квадрате+-(2x-2)(2x-2)=38