Question

За 9ч катер по течению проходит расстояние на 10 км меньше чем за 11 ч против течения реки. Скорость течения реки 2км/ч. Найти скорость катера в стоячей воде

Answer 1

Х  (км/ч) - скорость катера в стоячей воде (собственная скорость катера)
х+2  (км/ч) - скорость катера по течению
х-2   (км/ч) - скорость катер против течения

11(х-2) - 9(х+2)=10
11х-22-9х-18=10
2х=10+40
2х=50
х=25 (км/ч) - скорость катера в стоячей воде.
Ответ: 25 км/ч.

Answer 2

Problem Analysis

To find the speed of the boat in still water, we can use the following formula: Boat's speed in still water = (Speed downstream + Speed upstream) / 2

Given: - Time taken downstream (with the current) = 9 hours - Time taken upstream (against the current) = 11 hours - Speed of the current = 2 km/h - Distance traveled downstream = Distance traveled upstream

Calculations

Let's calculate the speed of the boat in still water using the given information.

The speed downstream can be calculated using the formula: Speed downstream = (Distance traveled downstream) / (Time taken downstream)

The speed upstream can be calculated using the formula: Speed upstream = (Distance traveled upstream) / (Time taken upstream)

The distance traveled downstream and upstream is the same, so we can use it for both calculations.

Solution

Using the given information and the formulas mentioned above, we can calculate the speed of the boat in still water.