Question

Номер 5 помогите пожалуйста

Answer 1

Log[2]cos(pi/12) + log[2]sin(pi/24) + log[2]sin(11pi/24)=
log[2]cos(pi/12) + log[2](sin(pi/24) * cos(pi/24)) =
log[2]cos(pi/12) + log[2](sin(pi/12) / 2 ) =
log[2](cos(pi/12) * sin(pi/12) / 2 ) =
log[2](sin(pi/6) / 4 ) =
log[2](1 / 8 ) = -3

Answer 2

log(2)cos(π/12) + log(2)sin(π/24) + log(2)sin(11π/24)=
=log(2)cos(π/12) + log(2)(sin(π/24)cos(π/24)) =
=log(2)cos(π/12) + log(2)(1/2*sin(π/12)  ) =log(2)(1/2*cos(π/12) sin(pi/12) ) =
=log(2)(1/4*sin(π/6)) =log(2)(1 / 4*1/2 ) = log(2)(1 / 8)=-3