Question

Найти х. 2lgx=lg33+lg5

Answer 1

$2lgx=lg33+lg5,\; \; \; \; x>0\\\\lgx^2=lg(33\cdot 5)\\\\x^2=165\\\\x_{1,2}=\pm \sqrt{165}\\\\Tak\; kak\; x>0,\; to\; x=\sqrt{165}\; -\; otvet$